b^2=36/49

Solution for b^2=36/49 equation:

b^2=36/49

We move all terms to the left:

b^2-(36/49)=0

We add all the numbers together, and all the variables

b^2-(+36/49)=0

We get rid of parentheses

b^2-36/49=0

We multiply all the terms by the denominator


b^2*49-36=0

Wy multiply elements

49b^2-36=0

a = 49; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·49·(-36)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*49}=\frac{-84}{98}
=-6/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*49}=\frac{84}{98}
=6/7
$